Question

54x
${54x}^{3} + {128y}^{3}$
(a
${x}^{3} + {y}^{3}$​

Answer 1

Answer:

x^3+y^3=(x-y)(x^2+xy+y^3)

then u can do ln the process

Answer 2

54a³ - 128y³

Factor 2 out of 54 +

2 (27 64y")

Rewrite 27³ as (32)

128y³

Rewrite 27³ as (32)

128y³

Rewrite 64y" as (47)³ 2 ((3x) - (4y)*)

Since both terms are perfect cubes, factor using the difference of cubes formula, a-b³- (a - b) (a² + ab +6²) where a = 3x and b4g. 2 ((3x − (4y)) ((3x)² +3 (4y) + (4y)²))

Factor

2(3-4y) (9² 12zy162)