Math, asked by yuditak, 6 months ago

55 : 1 : : 42 :8 : : 62 : 27 : : 93 :​

Answers

Answered by prashudwivedi54
1

Answer:

hope this help you!!!!!!!

Attachments:
Answered by KritikUpadhyay7
1

Answer:

Answer:

27

Step-by-step explanation:

Given :55:1::42:8::62:27::93:

To Find : Missing term

Solution :

55:1::42:8::62:27::93:

We observed that he second, fourth and the sixth numbers (1, 8, and 27) are the cubes of tens digit/ones digit.

(\frac{5}{5})^3 = (1)^3= 1(

5

5

)

3

=(1)

3

=1

(\frac{4}{2})^3 = (2)^3= 8(

2

4

)

3

=(2)

3

=8

(\frac{6}{2})^3 = (3)^3= 27(

2

6

)

3

=(3)

3

=27

(\frac{9}{3})^3 = (3)^3= 27(

3

9

)

3

=(3)

3

=27

Hence the missing number is 27.

Hope it's helpful to you.

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