Question

55:1::42:8::62:27::93:

Answer 1

Solution:-
The 2nd, 4th and 6th numbers (1, 8 and 27) are the cubes of  tens digit/ones digit.
i.e. (5/5)³ = 1
(4/2)³ = (2)³ = 8
(6/2)³ = (3)³ = 27
Similarly, (9/3)³ = (3)³ = 27
So, the the next number is 27
Answer.

Answer 2

Answer:

27

Step-by-step explanation:

Given :55:1::42:8::62:27::93:

To Find : Missing term

Solution :

55:1::42:8::62:27::93:

We observed that he second, fourth and the sixth numbers (1, 8, and 27) are the cubes of tens digit/ones digit.

$(\frac{5}{5})^3 = (1)^3= 1$

$(\frac{4}{2})^3 = (2)^3= 8$

$(\frac{6}{2})^3 = (3)^3= 27$

$(\frac{9}{3})^3 = (3)^3= 27$

Hence the missing number is 27