55: 1:: 42: 8 :: 62: 27 ::93 :?
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Solution:-
The second, fourth and the sixth numbers (1, 8, and 27) are the cubes of tens digit/ones digit.
i.e. (5/5)³ = (1)³ = 1
(4/2)³ =(2)³ = 8
(6/2)³ = (3)³ = 27
Similarly, (9/3)³ = (3)³ = 27
Therefore, the next in the series is 27
Answer.
The second, fourth and the sixth numbers (1, 8, and 27) are the cubes of tens digit/ones digit.
i.e. (5/5)³ = (1)³ = 1
(4/2)³ =(2)³ = 8
(6/2)³ = (3)³ = 27
Similarly, (9/3)³ = (3)³ = 27
Therefore, the next in the series is 27
Answer.
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