Question

55.5
18
28.0 g
2) The amount of CaO produced by decomposition one (1/4)fourth mole of CaCO3 will be
A 2.8 g B 8.4 g © 14.0 g 0
3) A mixture of two volatile liquids can be separated by​

Answer 1

We have to find the amount of CaO produced by decomposition 1/4 th mole of CaCO₃.

solution : we know, when one mole of limestone (CaCO₃) is heated, one mole of Calcium oxide and one mole of carbon dioxide are produced.

i.e., CaCO₃ => CaO + CO₂

∵ one mole of CaCO₃ = one mole of CaO

∴ 1/4 mole of CaCO₃ = 1/4 mole of CaO

molar mass of CaO = atomic mass of Ca + atomic mass of O = 40 + 16 = 56 g/mol

mass of 1/4 mole of CaO = 1/4 mol × 56 g/mol = 14g

Therefore 14g of CaO is produced by decomposition of 1/4 mole of CaCO₃.

Answer 2

$\huge \bold{\tt © 14.0 \: gm }$