Question

55. A solid compound AB has NaCl type structure. If the radius of the anion is 240 pm, then the radius of the cation (A+) will be (1) 99.36 pm (2) 20.75 pm (3) 240 pm (4) 200.52 pm​

Answer 1

Answer:

(1) 99.36 pm is the answer for your question

Explanation:

We know that, For NaCl structure with coordination number 6, we have radius ratio between 0.414−0.732

$\text{Radius ratio (r) is } r_c/r_a$

$Thus, \ r_c = r \times r_a$

For the maximum value of anion radius, we should have a minimum radius ratio =0.414

So,

$r_c = 240 \times 240\ pm\\r_c = 99.36 \ pm$

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