Math, asked by singhbhupender92, 10 months ago

55. If a +b=11, ab = 28, find the value of( a) 3+( b)3​

Answers

Answered by Rishirajplmokn
0

Answer:

a+b=11 and ab =28

(a+b)^2=11^2

a^2+b^2+2ab=121

a^2+b^2=121-2ab

a^2+b^2=121-2*28

a^2+b^2=65

And (a+b)^3=(a+b)(a^2-ab+b^2)

=11*(65-28)

=11*37

407

Similar questions