Question

55. The cost of energy to operate an
industrial refrigerator that consumes
5 kW power working 10 hours per day
for 30 days will be
(Given that the charge per kW.h of
energy = 4)​

Answer 1

Answer:

Rs 6000

Explanation:

Power (P) = 5 kW = 5 kW, Per day working time = 10 hrs, Total days = 30 days and Cost per unit = 4 per kWh

Total time (t) = 10 × 30 = 300 hrs

The total energy consumed by the industrial refrigerator in 30 days would be:

⇒ Energy (H) = P × t = 5 × 300 hrs = 1500 kWh

The cost of energy to operate the refrigerator for 30 days = total energy × cost per unit

⇒ Total cost = 1500 kW h × Rs 4 per kW h = Rs 6000