Question

550 kilo joules cycle inverse work is done by 1 mole of an ideal gas in a cyclic process .The amount of heat absorbed by the system in one cycle is

Answer 1

Answer:

Hint: This question can be solved by the formula ΔU=q+W, where ΔU is the change in the internal energy, q is the heat absorbed or evolved by the system, and W is the done by or on the system.

Complete step by step answer:

There are two types of functions in thermodynamics i.e., state function and path function. State functions are those properties that depend only on the initial and final state of the system but path functions are those properties that depend on the path of the system. So some examples of state functions are changes in internal energy, pressure, temperature, etc, and some examples of path functions are work done, heat, etc. So in a cyclic process, the initial point and the final point are the same, which means that those properties that are state functions will have zero value in the cyclic process because of the same initial and final point. As we know the first law of thermodynamics states that:

ΔU=q+W, where ΔU is the change in the internal energy, q is the heat absorbed or evolved by the system, and W is the done by or on the system.

So for a cyclic process, the ΔU will be zero. (it is a state function)

The equation will be:

q=W

So the amount of work done is equal to the heat absorbed by the system.

q=550 kJ / mol

Therefore, the correct answer is an option (a)- 550 kJ / mol.