Question

.55g of electron contains how many moles of electrons.

explain it ​

Answer 1

Mass of an electron = 9.1×10^-31 Kg

= 9.1×10^-28 g .

Then , number of electrons (say X) present in 0.55 g :

0.55/(9.1×10^-28) = 0.604×10^27

Further ;

no of moles (say n) = X/N

here N is Avogadro's constant .

=> n= 0.604×10^27/(6.023×10^23)

= 1003.4793

Hope it helps.