Question

56 4/7 kg of cement is packed equally in 18 bags . how many bags are required to pack 78 4/7 kg of cement​

Answer 1

Answer:

25 bags

Step-by-step explanation:

18 bags =56 4/7kg

1 bag = 396kg/18

1 bag =22 kg

NOW,

78 4/7 kg =550 kg

number of bags = total weight / weight of one bag

No. of bags= 550 / 22

No. of bags= 25..

Answer 2

Answer:

Given: 56 4/7 kg of cement is packed equally in 18 bags

To find: how many bags are required to pack 78 4/7 kg of cement​

Step-by-step explanation:

Solution:

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