Math, asked by mailtogauravin, 9 months ago

56/4/7kg of cement is paccked equally in 18 bags. How much bags are required to pack 78/4/7kg of cement

Answers

Answered by harshkushwaha189

7

56/4/7kg = 18 bags

56/28kg = 18 bags

2kg = 18 bags

1kg = 18/2

1kg = 9

78/4/7kg = 78/4/7*9

= 702/28

= 25.0714286

Answered by harsxp582

3

56/4/7kg = 18 bags

56/28kg = 18 bags

2kg = 18 bags

1kg = 18/2

1kg = 9

78/4/7kg = 78/4/7*9

= 702/28

= 25.0714286

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