Math, asked by kirankpriya2020, 2 months ago

56 - 64 ÷ 2 x 3 + 40
solve using DMAS rule​

Answers

Answered by neerugoswami10
0

Step-by-step explanation:

For example, multiplication is given a higher precedence than addition, and it has been this way right from the time when modern algebraic notations were introduced. Thus, the expression 3 + 5 × 2 is interpreted to have the answer 3 + (5 × 2) = 13, not (3 + 5) × 2 = 16. When exponents were introduced in the 16th and 17th centuries, they were given precedence over both addition and multiplication and are used as a superscript to the right of their base. Thus, 2 + 52 = 27 and 2 × 52 = 50.

These conventions exist to eliminate any ambiguity while enabling notation to be as brief as possible. Where it is desired to override the precedence conventions, or just to emphasize them, parentheses (), , { } can indicate an alternate order or reinforce the default order to avoid confusion. For example, (2 + 3) × 4 = 20 emphasize addition to precede multiplication, and (3 + 5)² = 64 emphasize addition to precede exponentiation.

What is BODMAS Rule?

BODMAS is a short form for Brackets, of, Division, Multiplication, Addition and Subtraction. In some regions, it is also known as PEDMAS - Parentheses, Exponents, Division, Multiplication, Addition and Subtraction.

This rule explains the order of operations (order of precedence) to solve an expression. According to BODMAS rule, in a given mathematical expression that contains combination of signs: brackets ((), {}, , −), multiplication, of, addition, subtraction, division, we must first solve or simplify the brackets followed by of (powers and roots etc.), of, then division, multiplication, addition and subtraction from left to right. Solving the problem without following BODMAS rule or from right hand direction will give you a wrong answer.

B

Brackets(−)

P (Parentheses)

O

Orders, Of,

E (Exponents)

D

Division ÷, /

D

M

Multiplication, *, x

M

A

Addition, +

A

S

Subtraction, -

S

Use of Bracket

Answered by Choudharipawan123456
0

Answer:

=> 0

Step-by-step explanation:

Given that:-

56-64\div2\times 3+40

To find:- 56-64\div2\times 3+40=?

To simplify the expression we have to use the DMAS rule:

D - division ( ÷ )

M - multiplication ( × )

A - addition ( + )

S - subtraction ( - )

As we have,

=> 56-64\div2\times 3+40

By further calculation we get,

Divide the numbers:

=>56-32\times 3+40

Multiply the numbers:

=> 56-96+40

Add the numbers:

=> 56 - 56

=> 0

Hence, the required solution is 0.

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