Question

56. A father is twice as old as his son 20 years
ago the age of the father was 12 times the
age of the son. The present age of the father
is:
(A) 44 years
(C) 22 years
(B) 32 years
(D) 50 years
.
.​

Answer 1

Answer: Option C

Step-by-step explanation:

Let sons age = x. Then, fathers age = 2x.

12(x—2O) = (2x - 20) so x = 22

Father's present age = 44 year

Answer 2

Answer:

$\large\boxed{\sf{(A)\:44\;years}}$

Step-by-step explanation:

Let the present age of son = x yrs.

.°. The present age of father = 2x yrs.

20 years ago

Age of son = (x -20) yrs.

Age of father = (2x -20) yrs.

According to question,

20 yrs. ago, father was 12 times the age of son

Therefore, we will get the equation,

$= > 2x - 20 = 12(x - 20) \\ \\ = > 2x - 20 = 12x - 240 \\ \\ = > 12x - 2x = 240 - 20 \\ \\ = > 10x = 220 \\ \\ = > x = \dfrac{220}{10} \\ \\ = > x = 22$

Therefore, present age of son = 22 yrs.

Hence, present age of father = (A) 44 yrs.