Question

56. Anhydrous soldium salts of fatty acids on heating with soda lime (NaOH+Cao) gives...
(A) Alkene
(B) Alkeane
(C) Alkyne
(D) None of these​

Answer 1

Answer:

Alkanes

Explanation:

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Answer 2

Answer:

B) alkanes

The reaction is termed as decarboxylation reaction since it involves the removal of carbon dioxide.