Question

56. Anu and Bhuvan together can complete a work in 8 days, while Bhuvan and Chirag can together do
.41(2/3)% of that work in 5 days. All of them can complete double of the original work in 12 days. In how
many days Anuj and Chirag can do that work?​

Answer 1

Answer with explanation:

Time taken by Anu and Bhuvan to Accomplish a piece of work = 8 days

Let time taken by , Anu to accomplish this work alone= x days

And, Time taken by , Bhuvan to accomplish this work alone= y days

Time taken by Bhuvan and Chirag to complete $41\frac{2}{3}=\frac{125}{3}$percent of work =5 days

Let, Time taken by , Chirag to accomplish this work alone= z days

$\frac{125}{3}\Pr\text{ work} =5 \text{days}\\\\1 \text{day}=\frac{25}{3}\Pr\text{ work}\\\\12 \text{day}=100\Pr\text{ work}$

Time taken by all the three to complete double of the work together = 12 days

Time taken by all the three to complete same work together = 6 days

Writing all the statement in terms of equation and then solving

$1.\frac{1}{x}+\frac{1}{y}=\frac{1}{8}\\\\2.\frac{1}{z}+\frac{1}{y}=\frac{1}{12}\\\\3.\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{1}{6}\\\\ 1 +2\\\\\frac{1}{x}+\frac{2}{y}+\frac{1}{z}=\frac{1}{8}+\frac{1}{12}\\\\4.\frac{1}{x}+\frac{2}{y}+\frac{1}{z}=\frac{5}{24}\\\\2 \times \text{equation 3}\\\\5.\frac{2}{x}+\frac{2}{y}+\frac{2}{z}=\frac{1}{3}\\\\ \text{Eq.5 -Eq.4}\\\\\frac{1}{x}+\frac{1}{z}=\frac{1}{3}-\frac{5}{24}\\\\\frac{1}{x}+\frac{1}{z}=\frac{1}{8}$

Anuj and chirag can accomplish the work in 8 days.