Question

56 Find the compound interest on 1000 for 2 years at 5% per annum Ops: A ORs 10250 B ORs 110250 C 0 Rs.
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Answer 1

Step-by-step explanation:

Given, principle (P) = 1000 /-

Given, principle (P) = 1000 /-Time (t) = 2 years.

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest =

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.=

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.= 100

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.= 100100×2×5

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.= 100100×2×5

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.= 100100×2×5 =100/−

Given, principle (P) = 1000 /-Time (t) = 2 years.Rate of interest (r) = 5 %We know, simple interest = 100P.t.r ∴S.I.= 100100×2×5 =100/− ∴ Simple interest is Rs. 100

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