Question

56. From 440 mg of CO 1020 molecules of Co, are
removed. The total number of remaining atoms will be
(1) 1.51 x 1020
(2) 2.89 1021
(3) 1.77 1022
(4) 1.46 10​

Answer 1

Answer:

In 440mg contains CO moles=440×10^-3 ÷28 = 15.7142857 ×10^-3 moles

And 10^20 molecules in moles= 10^20 ÷ 6×10^23 = 1.66 × 10^-3 moles

Now ,

after removing 10^20 molecules remaining molecules(in form of moles)= 14.0542857 × 10^-6 moles

Now, remaining in form of atoms= mole × Na × atomicity(for CO=2) =14.0542857 × 10^-6 × 6 × 10^23 × 2 = 168.651428 × 10^17 atoms = 1.68651428 × 10^20(answer)

So approx. Your answer is 1.77 × 10^20

Explanation:

Hope you get the answer

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Answer 2

Answer:as I think your answer will be the third option

Explanation: