Question

56 g of Nitrogen reacts with 22 g of hydrogen to form ammonia.Find

I) The limiting reagent of the reaction.

2) The amount of reactant in excess

3) The amount of ammonia formed.

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Answer 1

Answer:

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Answer 2

Answer:

56g of N2+10g of H2

N2(g)+3H2(g)→2NH3(g) 

In the given reaction, 1 mol of N2 reequires 3 moles of H2 for the formation fo ammonia.

Thus if the number of moles of N2 and H2 should be in ratio 1:3.

We know,

n=molecular weightweight

Thus in option C 56g of N2 means 2 moles of N2 and 10g of H2 means 5 moles of H2.

Thus here H2 acts as limiting reagent

Explanation:

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