Question

56 gm of calcium oxide contains..............................................
a)60.23*10^23 atoms of calcium oxide
b)6.023*10^23 molecules of calcium oxide
c)0.6023*10^23 molecules of calcium oxide
d)0.06023*10^23 molecules of calcium oxide

Answer 1

Answer:

B) the option is be 6.023*10'23

Answer 2

Answer:

Explanation:

According to the Avagadro's constant one mole of any element or a compound contains definite 6.023 × 10²³ molecules of the compound or atoms of an element.

Molar mass of calcium = 40

Molar mass of oxygen = 16,

Therefore the molar mass of CaO will be 40 + 16 = 56g/mol

Calculating the moles of CaO:

Moles  = mass/molar mass

= 56 grams / 56gmol⁻¹

= 1 mole

Therefore,  56 grams of moles of Calcium Oxide is 1 mole

Since as per the Avogadro's number one mole of any compound has exaclty 6.023 × 10²³ molecules of that compound, thus there will be 6.023 × 10²³ molecules of CaO in 56g of Calcium Oxide.