Question

56 gm of CaO react with 63 gm of HNO3 mass of Ca(NO3)2 formed will be?​

Answer 1

CaO + 2HNO₃ ----> Ca(NO₃)₂ + H₂O

Molar Mass:

CaO = (40+16) g = 56 g

2HNO₃ = 2*(1+14+48) g = 126 g

Ca(NO₃)₂ = 40+2*(14+48) g = 164 g

H₂O = (2+16) g = 18 g

This means 126 g of Nitric Acid has been taken to produce 164 g of Calcium Nitrate.

So, 63 g of Nitric Acid will produce = (164/126)*63 g of Calcium Nitrate

= 82 g of Calcium Nitrate

I hope this helps.