Question

56 GM of n2 of 9gm of h2 in a closed vessels to form nh3 which reactant is left in excess and how much​

Answer 1

Answer:

N2,.

0.5mol is left in excess

Explanation:

no.of mol of N2 = 56g/28g/mol= 2mol

no.of mol of H2= 9g/2g/mol = 4.5 mol

N2 + 3H2 = 2NH3

from stoichiometry of the reaction,

3 mol H2 = 1molN2

4.5 mol H2 = 1.5 mol N2

hence, N2 is left in excess.

the amount of N2 left = 2- 1.5 = 0.5mol