Chemistry, asked by rohanmalhotra1540, 3 months ago

56 gram N2 react with 14 gram hydrogen to from NH3 gas then calculate first which is the limiting reagent second calculate the maximum amount of NH3 that can be formed third calculate the amount of reactant left and reactant

Answers

Answered by uditm689
0

Answer:

The ba;lanced reaction is as follows:

N2+3H2→2NH3

28 g     6 g     34 g

14 g      6 g  (Given)

14 gm    3 gm  (Actually consumed)

Here, nitrogen is limiting reagent so, excess hydrogen left is 3 g.

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