Question

56 gram of N2 reacts with 30 gram of H2 to form NH3 calculate the number of moles of NH3

Answer 1

Answer:

the name of this reaction is Haber's process.

N2+ 3H2 = 2NH3

in this reaction nitrogen is the limiting reagent. now we calculate the number of the moles of nitrogen and hydrogen respectively which is 2 moles and 15 moles

( no. of moles of nitrogen = 56/28)

(no. of moles of hydrogen = 30/2)

hence by the law of stoichiometry and basic math

no. of moles of ammonia = 2 x 2 /1 = 4 moles.

hope this helps mate