Question

56 grams of nitrogen is
present in 5 litre solution,
the active mass of
nitrogen is​

Answer 1

Answer:

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Answer 2

Given:

The mass of nitrogen, w = 56 gm

The volume of solution, V = 5 L

To Find:

The active mass of nitrogen.

Calculation:

- The no of moles of nitrogen, n = w/M.wt

⇒ n = 56/14 = 4

- Active mass is expressed as no of moles per litre.

⇒ The active mass of Nitrogen = n/V

⇒  Active mass = 4/5 = 0.8 moles/L

- So, the active mass of nitrogen in the given solution is 0.8 moles/litre.