Question

56 grams of nitrogen is present in 5 litre solution, the active mass of nitrogen is

Answer 1

Answer:

• The active mass of Nitrogen is 0.4 mol/L

Given:

1. Given mass of Nitrogen (m) = 56 g
2. Volume of the solution (V) = 5 litre

Explanation:

$\rule{300}{1.5}$

Firstly finding the moles,

$\displaystyle\dashrightarrow\;\boxed{\sf Moles\;(n)=\dfrac{Given\;Weight\;(m)}{Molar\;Mass(W)}}$

Substituting the values,

$\displaystyle\dashrightarrow\sf n=\dfrac{56}{28}\\\\\\\dag\;\sf N_{2}=2\times14=28\;(W)\\\\\\\dashrightarrow\sf n=\dfrac{56}{28}\\\\\\\dashrightarrow\sf n=\cancel{\dfrac{56}{28}}\\\\\\\dashrightarrow\sf n=2\\\\\\\dashrightarrow \large{\underline{\underline{\sf n=2 \; moles}}}$

$\rule{300}{1.5}$

$\rule{300}{1.5}$

Now, from active mass formula,

$\displaystyle\dashrightarrow\;\boxed{\sf Active\;Mass=\dfrac{Mole}{Volume}}$

Substituting the values,

$\displaystyle\dashrightarrow\sf [N_{2}]=\dfrac{2}{5}\\\\\\\dag\; \sf [N_2]\;Denotes\;Active\;Mass\;of\;N_2\\\\\\\dashrightarrow\sf [N_{2}]=\dfrac{2}{5}\\\\\\\dashrightarrow\sf [N_{2}] = 0.4\\\\\\\dashrightarrow \large {\underline{\boxed{\red{\sf [N_{2}] = 0.4\;mol/L}}}}$

∴ The active mass of Nitrogen is 0.4 mol/L.

$\rule{300}{1.5}$