Question

56 in four parts in A.R such that the ratio of the product of their extremes (1st and 4th) to the product of means (2nd and 3rd) is 5 : 6

Answer 1

Answer:

Divide 56 in four parts in AP, such that the ratio of the product of extremes to the product of means is 5:6. Hint: Assume that the first term of the formed A.P is a and the common difference is d. Hence the number will be a, a+d,a+2d,a+3d. ... Hence the numbers are a, a+d, a+2d

Answer 2

Answer:

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