Question

56 kg of N2 and 10 kg of H2 is mixed with to produce NH3 calculate the number of moles in ammonia is formed​

Answer 1

N2+3H2 》2NH3

Moles of N2 = 56×10^3/28 =2 ×10^3

Moles of H2= 10×10^3 /2 = 5 ×10 ^3 moles

1 mole N2 forms 2 moles ammonia so 2 ×10 ^3 will form 4 ×10^3 moles ammonia

3 moles of H2 will form 2 moles of NH3 so 5×10^3 moles will form 2/3 ×5×10^3 = 3.33 ×10 ^3 moles

Clearly H2 is limiting reagent so ammonia formed will be 3.33×10^3 moles