.56 mole of ammonia has mass of
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Given ;
- Ammonia = NH3
- n(NH3) = 0.56
- M(NH3) = 1(14) + 3(1) = 14 + 3 = 17
Thus we know that : n = W/M
- n = W/M
- W = n×M
- W = 0.56 × 17
- W = 9.52 g
#answerwithquality
#BAL
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