Question

56. The distance travelled by a body during last second of its total flight is d when the body is projected
vertically up with certain velocity. If the velocity of projection is doubled, the distance travelled by
the body during last second of its total flight is


Please answer fast​

Answer 1

Answer:

d

Explanation:

The distance travelled by a body during last second of its total flight is d when the body is projected  vertically up with certain velocity. If the velocity of projection is doubled, the distance travelled by  the body during last second of its total flight is

Let say Velocity = V

Velocity at Peak = 0

time taken to reach at peak = T

0 = V - gT

=> T = V/g

Velocity at T - 1 Sec = V - g(T-1) = V - g(V/g - 1)  = V - V + g = g m/s

Distance covered in Last sec using V² - U² = 2aS

=> 0² - g² = 2(-g)d

=> d = g/2

Now Velocity = 2V

=> T = 2V/G

Velocity at T - 1 Sec = 2V - g(T-1) = 2V - g(2V/g - 1)  = 2V - 2V + g = g m/s

=> 0² - g² = 2(-g)s

=> s = g/2

=> s = d

distance traveled by the body during the last  second of its upward journey is​ same  d

Answer 2

Explanation:

step by step explanation