Question

56.
What is the potential of the cell containing two
hydrogen electrodes as represented below
Pt; H2(g) | H(10-3M || H+(0.001 M) | H2(g).Pt;
(1) - 0.295 V
(2) -0.0591 V
(3) 0.295 V
(4) 0.0591 V​

Answer 1

Explanation:

Since oxidation occurs.

H

2

→2H

⊕

+2e

−

Q=[H

⊕

]

2

=10

−14

MinH

2

O

E=E

⊖

−

2

0.0591

log10

−14

=0+0.0591×7=0.4137V