Math, asked by sunithav343, 11 months ago

560 students of a school have to walk behind a group of 32 teachers of a school in a march against corruption. The two groups are to march in the same number of column. i) What is the maximum number of columns in which they march? ii) Which value depicted by the students and teachers?

Answers

Answered by santoshmaneesh1010
1

16 is the answer..

HCF of 560 and 32 is 16

Answered by windyyork
6

Given :

Number of students = 560

Number of teachers = 32

To find : the maximum number of columns in which they march = ?

Solution :

For the maximum number, we will find HCF :

So, HCF of 560 and 32  = 16

So, the number of students in each column would be :

\dfrac{560}{16}=35

the number of teachers in each column would be:

\dfrac{32}{16}=2\\

Hence, there are 16 maximum columns.

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