Math, asked by madhusahni, 1 year ago

₹ 561 are divided among A,B and C such that A's share is₹120 more than B's share and ₹120 less than C's. B's share will be

Answers

Answered by Ankit02
5

Let all the shares be x .
then 
A share = x+120
B share = x 
C share = x +120
Then,
x+120+x+x+120 = 561 
3x = 561 - 240
x = 321/3
x = 107 


so  B share = 107 ruppes 

madhusahni: answer is 67
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Answered by mohammedraiyanp2alyt
7
Total money = 561
Let B's share be x.
A's share = 120+ x
C's share = 120 + 120 + x = 240 + x
ATQ,
120 + x + 240 + x + x = 561
360 + 3x = 561
3x = 561 - 360 = 201
x = 201/3 = 67
Therefore, B's share = 67
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