Question

56g of n2 reacts 9g of h2 in a closed vessel to form nh3. which reactant is left and how much​

Answer 1

answer=N  

2

​  

     +     3H  

2

​  

        →    2NH  

3

​  

 

2                  4                        0

2−x         4−3x                    2x

According to the question, 2x=2=>x=1

Hence at equilibrium,

number of moles of N  

2

​  

=2−x=2−1=1

number of moles of H  

2

​  

=4−3x=4−3=1

number of moles of NH  

3

​  

=2x=2