Question

56g of nitrogen reacts with 30g of hydrogen to form ammonia.calculate the number of mole in ammonia
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Answer 1

Answer:

Nitrogen (56g) reacts with hydrogen (30g) to form ammonia.

To Find :

⟶ No. of moles of ammonia formed.

SoluTion :

➢ Stoichiometry deals with the calculation of moles of the reactants and the products involved in a chemical reaction.

➢ The substance which is completely consumed in the reaction and limits the amount of product formed is called limiting reagent.

✴ Balanced chemical reaction :

\bigstar\:\underline{\boxed{\bf{\green{N_2+3H_2}\:\purple{\longrightarrow}\:\red{2NH_3}}}}★

N

2

+3H

2

⟶2NH

3

⇒ 6g H_2

2

rects with 28g of N_2

2

Therefore, 30g H_2

2

reacts with

30/6 × 28 = 140g of N_2

2

✭ Hence, N_2

2

is the limiting reagent.

➠ 28g of N_2

2

produces 2 moles of NH_3

3

Therefore, 56g of N_2

2

will produces

56/28 × 2 = 4 moles of NH_3

3

Answer : 4 moles of NH