Question

56xsquare, -49xy factorization​

Answer 1

Step-by-step explanation:

=56x^2-49xy

=7x(8x-7y) hope it helps you

Answer 2

$find \: the \: gcf$

$What \: is \: the \:  largest \: \\ number  \: that \: \\ divides \\ evenly \: into \: \\  56{x}^{2} and -49xy$

$it \: is \: 7.$

$What \: is \: the  \: highest \: degree \: \\ of  \: x \: that \\ divides \: evenly \: into \: \\  56{x}^{2}and -49xy?$

$it \: is \: x$

$What \: is \: the  \: highest \: degree \\ of  \: y \: \\ that \: divides \: evenly \\ \: into \:  56{x}^{2}and -49xy?$

$It \: is \: 1, \: since y \:  is \: \\ not \: in \: every \: term.$

$so \: gcf \: is \: 7x$

$Factor \: out \: the \: GCF. \: (Write \: the \\ GCF \: first. \: Then, \: in \\ parentheses, \: divide \\ each \: term \: by \\ the \: GCF.)$

$7x( \frac{56 {x}^{2} }{7x} + \frac{ - 49xy}{7x} ) so\: now the \: last \:step</p><p>$

$Simplify \: each \: term \: in \: \\ \: parentheses.$

$7x(8x - 7y)$