57÷[{10+5)-3×2}+10] solution
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Answered by
34
57÷[{15-3×2}+10]
57÷[{15-6}+10]
57÷[9+10]
57÷19
3 Ans
57÷[{15-6}+10]
57÷[9+10]
57÷19
3 Ans
Answered by
2
Answer:
FIRSTLY OPEN BRAKET=
~~~~~~~~~~~~~~~~~~~~~
=450÷ [70+(30+70)-50-30)]
=450÷ [70+100-80]
=450÷90
=450/90
=5
~~~~
THANKS HOPE IT WILL HELP YOU
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