Question

57. How much torque of couple is produced due to two equal forced each of magnitude 10N acting on a rod
of 400cm, If one force acts at left end and second force is applied at a distance of 50cm from the center of
rotation on right side?
A. 25Nm
B. 20Nm
C. 40Nm
D.35 Nm
​

Answer 1

Answer:

Magnitude of force applied on each end = 10 N .

The moment of force τ = r × F. Hence in bothe the cases, moment of force is in the clockwise direction, and the moment of forces add to one another.

The magnitude of τ = 2 × 10 × 2 = 40 Nm in the clockwise direction.