Question

57.
If the sum of the first 40 terms of the series, 3+4+8+9+13+14+18+19........... is
(102)m, then m is equal to:
1) 20
2) 25
3) 10
4) 5
​

Answer 1

please go through attachment, hope this helps!!

Answer 2

Answer:

Correct option (1)

Step-by-step explanation:

S=3+4+8+9+13+14+18+19+....40 terms  = 7+17+27+37+...20 terms

it is in A.P

∴s=  20/2  [2×7+(20−1)10]

=10(14+190)

=10×204

=20×102

as s=(102)m

⇒20×102=102×m

m=20