Question

57. If x= a coso, y = b sin, then
x^2+y^2/a^2+b^2=​

Answer 1

Answer:

x=acosθ;y=bsinθ

cosθ=

a

x

;sinθ=

b

y

cos

2

θ+sin

2

θ=1=

a

2

x

2

+

b

2

y

2

x

2

b

2

+a

2

y

2

=a

2

b

2

.