Question

57. The Eºcell Cu/Cu? || Ag' / Ag is (1M) (0.1M) Ag' +e-Ag E' = 0.799 Cu2+ + 2e > Cu E° = 0.34V OA) 0.415V OB) 0.374 V OC) -0.415 V OD) -0.374 V​

Answer 1

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Given Zn∣Zn2+(0.001M)∣∣Cu2+(0.1M)∣Cu

Overall cell reaction:

Zn⟶Zn2++2e−Cu2++2e−⟶CuZn+Cu2+⟶Zn2++Cu

Ecello=standard reduction potential of cathode + standard oxidation potential of anode

Ecello=0.34 to 0.76 V

Ecello=1.1 V

KC=[Cu2+][Zn2+]=10−110−3=10−2

EMF of the cell at any electrode concentration is:

E=Eo−n0.059log(KC)=1.1−20.059log(10−2)=1.

Explanation:

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