Question

57. The income of X is 60% more than Y's
income and the income of Y is 40% more
than Z's income. X's income is how
much percentage more than Z's income?
(a) 134%
(b) 224%
(C) 100%
(d) 124%
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Answer 1

Answer:

X's income is 224% more than Z's income. (option d)

Step-by-step explanation:

Given:

Income of X = 60% more than income of Y.

Income of Y = 40% more than income of Z.

Asked:

How much % income of X is more than income of Z.

Solution:

Let the income of Z be 100',

So, Income of Y = 100 + (40% of 100)

⇒ 100 + ($\frac{40}{100}$ × 100)

⇒ 100 + 40

⇒ 140

Income of Y = 140

We know that Income of X is 60% more than income of Y.

So, Income of X = 140 + (60% of 140)

⇒ 140 + $(\frac{60}{100}$ × 140)

⇒ 140 + 84

⇒ 224

Income of X = 224

Now we got the Income of X, so we need to find the how much % is Income of X more than Income of Z.

So, $\frac{224}{100}$ × 100%

⇒ 224%

Therefore,

Income of X is 224% more than Income of Z.

Answer 2

Step-by-step explanation:

upper one is correct

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