57.The magnifying power of the objective of a compound microscope is 7.If the magnifying power of the microscope is 35, then the magnifying power of eye piece will be --------
Answers
Answered by
21
M=Me × Mo
Where M= Magnifying power
Me= Magnifying power of eye piece
Mo= Magnifying power of objective
Me=M÷Mo
Me=35÷7
Me=5.
Where M= Magnifying power
Me= Magnifying power of eye piece
Mo= Magnifying power of objective
Me=M÷Mo
Me=35÷7
Me=5.
Similar questions