Physics, asked by akashomegakanpur, 11 months ago

57.
There is an inclined surface of inclination 0 = 30°.
A smooth groove is cut into it forming angle a with
AB, A steel bal is free to slide along the groove. If
the ball is released from the point o at top end of
the groove, the speed when it comes to A is : [g =
10m/s)
Fixed
O
4m
A
+
B
3m
(a) V40m/s
(c) V10m/s
(b) (20m/s
(d) 15m/s
i
biu​

Answers

Answered by titu36
2

Explanation:

The plane is inclined at 30∘ to horizontal and the path of the cylinder is at 30∘ to OX

Therefore the acceleration of cylinder

a=(gsin30∘)(sin30∘)

=10(12)(12)

=2.5m/s2

time taken =t=2sa−−−√

=2×52.5−−−−√

=2s

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