Question

58.5 g of sodium chloride is dessolved in 180 g of water. calculate the mole fraction of sodium chloride in the solution.​

Answer 1

Answer:

1/11

Explanation:

mole fraction=x1/(x1+x2)

X1=mole of NaCl=1

X2 = mole of H2O=10

mole fraction =1/1+10=1/11

Answer 2

The mole fraction of sodium chloride in the solution. is 0.091

Explanation:

Mole fraction is the ratio of moles of that component to the total moles of solution.

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

And,

$n_A=\frac{m_A}{M_A}$

Mole fraction of sodium chloride is given as:

$\chi_{NaCl}=\frac{\frac{m_{NaCl}}{M_{NaCl}}}{(\frac{m_{H_2O}}{M_{H_2O}}+\frac{m_{NaCl}}{M_{NaCl}})}$

Molar mass of $NaCl$= 58.5 g/mol

Molar mass of $H_2O$ = 18 g/mol

Putting values in above equation, we get:

$\chi_{NaCl}=\frac{\frac{58.5g}{58.5g/mol}}{(\frac{180g}{18g/mol}+\frac{58.5g}{58.5g/mol})}$

$\chi_{NaCl}=0.091$

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