Question

58. A block of mass 10 kg, moving with acceleration 2 m/s2 on horizontal rough surface is shown in figure
→ a= 2 m/s
→F=40N
The volna ofenofficient of kinetic friction is​

Answer 1

Answer:

0.20

Explanation:

We are given that a block of mass 10 kg moving with acceleration $2m/s^2$ on a rough horizontal surface

We have to find the value of coefficient of friction means value of $/mu$

Mass of block=10 kg

a=2$m/s^2$

g=9.8$m/s^2$

External force applied=40 N

Friction force=$\mu mg$

Friction force =$\mu\times 10\times 9.8=98\mu$

When a particle moving with acceleration it means external force applied os greater than the friction force

Net force =External force= friction force

$m\times a=40-98\mu$

$2\times 10=40-98\mu$

$98\mu=40-20=20$

$\mu=\frac{20}{98}=\frac{10}{49}=0.20$

Hence, coefficient of friction =0.20

Answer 2

Answer:

0.2

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