Question

58). A body dropped from top of a tower fall through 40 m during the last two seconds of its
fall. The height of tower is : (g = 10 m/s-)
a) 60 m
b) 45 m
c) 80 m
d) 50 m
l​

Answer 1

Answer:

Here time taken will be 3 seconds

Now , u = 3 × 10 = 30 m/s

height , H = u^2/2g

H = 900/20

Therefore the height will be 45 metres

HOPE IT MAY BE HELPFUL

MARK ME AS BRAINLIEST

FOLLOW ME

BE HAPPY

GOOD LUCK

Answer 2

✿━━━━@Mg━━━━✿

$\boxed{Explained\:Answer}$

______________________________

✿━━━━@Mg━━━━✿

$\mathfrak{\huge{\red{ANSWER}}}$

58). A body dropped from top of a tower fall through 40 m during the last two seconds of its

fall. The height of tower is : (g = 10 m/s-)

a) 60 m

b) 45 m✔✔

c) 80 m

d) 50 m

l