Question

58. A copper wire of mass 20 g carries a current of 6.023
A: What fraction of the total number of free elec-
trons present in copper wire flows through the cross-
section of the copper wire in 2 s?
(gram atomic weight of copper = 63.5 g)​

Answer 1

Answer:

2*(number of free electrons crossing unit area pf wire per second/number of free electrons in 20g of copper)

Explanation:

We need to find the fraction of total number of free electrons, present in copper wire flows through  the cross section of copper in 2 seconds

current I = 6.023

number of free electrons crossing unit area of wire per second =(6.023/1.6 E-19).

number of free electrons in 20g of copper= N x (20/63.5) where N is the Avogadro number.

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Answer 2

Answer:

number of free electrons crossing unit area of wire per second =(6.023/1.6 E-19). number of free electrons in 20g of copper= N x (20/63.5) where N is the Avogadro number. Iam telugu person plz fallow back........