Question

58. A projectile is thrown from the ground as
shown. The distance between two vertical
walls is 90 m. The range of projectile is​

Answer 1

The projectile is at a height h at t=2 and t=6 seconds .

h=usinθt−

2

1

gt

2

at t=2 ,

h=2usinθ−2g

at t=6,

h=6usinθ−18g

∴4usinθ=16g

usinθ=4g=40...(i)

As the separation between the 2 points is 120 m,

u cosθ×Δt=120

4ucosθ=120

ucosθ=30....(ii)

Dividing equation (i) by (iii)

tanθ=

3

4