Question

58. In which of the following the hybridisation of
the central atom is not the same as in others
1) 13
2) XeF2
3) CIF:
4) HClO4​

Answer 1

Answer:

please mark me as

Explanation:

ANSWER

In BF

3

, the ground state electronic configuration of Boron is 1s

2

2s

2

2Px

1

. excited state electronic configuration

is 1s

2

2s

1

2Px

1

2Py

1

One electron from one

′

s

′

orbital and two electrons from

′

p

′

orbital overlaps with

′

p

′

orbital electrons of Flourine to form three sp

2

hybridised bonds. So, BF

3

has sp

2

hybridisation.

Flourine (a)

But in H

3

O

+

,NH

3

and PCl

3

, the hybridisation involves one electron from

′

s

′

orbital, 3 electrons for

′

p

′

orbitals in central orbital forming sp

3

hybridisation.

solution

Answer 2

Answer:

The answer is BF³ so in that options I think so 1option.

hope,it helps to you.